(3x-5)(5-x+1)^2=30

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Solution for (3x-5)(5-x+1)^2=30 equation: 



(3x-5)(5-x+1)^2=30

We move all terms to the left:

(3x-5)(5-x+1)^2-(30)=0

We add all the numbers together, and all the variables

(3x-5)(-1x+6)^2-30=0

We multiply parentheses ..

(-3x^2+18x+5x-30)^2-30=0

We move all terms containing x to the left, all other terms to the right

(-3x^2+18x+5x-30)^2=30

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